E^4x = 20. solve for x. How do i work this out?

Dont quite understand this concept. can any 1 help me?E^4x = 20. solve for x. How do i work this out?
If you mean lower case ';e'; (a symbol for a mathematical constant) then its a logarithmic problem.





Natural Root is the LN key on your calculator, LN(e^1) = 1





So if,


e^4x=20


then,


ln(e^4x)=ln(20)


You can take the natural root of both sides of the equation, remember ln(e) cancels to 1, so you get:


4x=ln(20)


then just divide by 4 to get x.





x=(ln(20)/4)


or rounded


x= ~0.7489





but leaving it in fraction form is more accurate.E^4x = 20. solve for x. How do i work this out?
e^(4x) = 20


4x = ln 20


x = (1/4) ln 20
take ln both sides ---%26gt;4x = ln20 ----%26gt;x= 0.75
e^4x = 20





Since ln (natural log) is log with the base e (instead of 10 or whatever else), you have to take the ln of the whole thing.





ln(e^4x) = ln20





Log properties time... Exponents in a log go out front.





4x(lne) = ln20





Because the base of a ln is e, the e in the problem cancels out, leaving you with...





4x(1) = ln20





4x = ln20





x = (ln20)/4





x is about .749