How do you work this out?

It isn't hard, for you all, apart from me.





Xlog 3=(X+1)log 2





Please help!





Show me the steps...How do you work this out?
xlog3 = (x+1)log2





distribute


xlog3 = xlog2 + log 2


xlog3-xlog2 = log2


x(log3-log2) = log2


xlog(3/2) = log2


x= log2 / log(3/2)


x= 1.7095How do you work this out?
xlog(3) = xlog(2) + log(2


x(log(3) - log(2)) = log(2)


x = log(2)/(log(3) - log(2))


x = log(2)/(log(1.5)


x = 1.709511
Remember that log 3 and log 2 are constants, so first treat them just like any other coefficients:





X*log(3)=(X+1) log(2)


X*log(3)=X*log(2) + log(2)


X*log(3) - X*log(2) = log(2)


X(log(3) - log(2)) = log(2)


x = log(2) / (log(3) - log(2))


x = log(2) / log(3/2)
first log3 and log2 are just numbers


xlog3=xlog2+log2


xlog3-xlog2=log2


x(log3-log2)=log2


x=log2/(log3-log2)
xlog3 = xlog2 +1log2


xlog3 - x log2 = log 2


x(log3 - log2) = log 2


x = log2 / (log3 - log2)
if you wrote this correctly, this is not a ';log'; equation, as the log3 and log2 are just constants (numbers). Just imagine how you would solve this if they had written 3 and 2 instead, and do the same thing:





xlog3 = xlog2 +1log2


xlog3 - x log2 = log 2


x(log3 - log2) = log 2


x = log2 / (log3 - log2)
Xlog 3=(X+1)log 2


.4771*X=.3010*X+.3010


.1759*X=.3010


X=.3010/.1759=1.7095