A 10-gauge copper wire (diameter = 2.588 mm, ρ = 1.7 × 10–8 Ω · m) has a total resistance of 0.32 Ω. How long is the wire?How do I work this out? Physics?
R=p.L/A
resistance is equal to product of resistivity and length divided by the area of the conductor.
so then: R.A=p.L ............ok??!!
so then L= R.A/p - that will give the value you need .
the first equation above is what you need to do the calcs.
gmcn.How do I work this out? Physics?
http://espanol.weather.com/weather/today…
(for the Spain weather question)
Use the formula R = (p*l)/a and plug in you values. That gives you l = (2.588*.32)/(1.7*10^-8)
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